Build array index ranges of an integer in C# .NET

Suppose that we have a large array of data heavy objects that are impractical to handle in a single go. Instead we can read batches of the array until all elements have been processed. It can then be useful to build a range of indexes for the objects in the array that we want to extract.

E.g. if an array consists of 357 objects and we want to read at most 100 elements from it in a single batch then the size of the batches will be as follows:


…and we want to extract the elements by their indexes as follows:

0, 99
100, 199
200, 299
300, 356

…where the first number is the array start index and the second number is the array end index. Since we’re talking about array indexes the numbers are 0-based of course.

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Building an integer sequence using the Range operator in LINQ C#

Say you need a list of integers from 1 to 10. The traditional way is the following:

List<int> traditional = new List<int>();
for (int i = 1; i <= 10; i++)

There’s a more concise way to achieve this with the static Range method which accepts two parameters. The first integer in the sequence and a count variable which defines the number of elements in the list. The step parameter is 1 by default and cannot be overridden:

IEnumerable<int> intRange = Enumerable.Range(1, 10);
foreach (int i in intRange)

This will print the integers from 1 to 10.

Say you need an integer list from 100 to 110 inclusive:

IEnumerable<int> intRange = Enumerable.Range(100, 11);

View the list of posts on LINQ here.

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